bluestreak711
Rookie
Is there a forum with homework help or can someone help me here?
(Please see last page on forum.)
(Please see last page on forum.)
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Algebra Yikes!
- Thread starter bluestreak711
- Start date
forzainter
Semi-Pro
try bbc bitesize, type into google 'bbc scotland bitesize' and then go into maths and if you are 14 - 15 - 16 click standard grade and if you are older click higher or advanced higher
ilovecarlos
Professional
Is there a forum with homework help or can someone help me here?
Lotsa luck there...it took me 2 years to pass algebra (geometry is MUCH easier) and I'll tell you what....I've never ever used it...I do not care what
x =........it should be abolished...along with those, "two trains leave different stations at the same time" problems....Hey, I know..let's ban math period!!!
Kobble
Hall of Fame
Math for the sake of math had driven me crazy before college. Schools need to show people how to apply what they have learned. Check the web, though. You can find sites that break it down for you with good anaologies. My advice, learn the applications and it will stick better. Otherwise it is like learning a language without the intention of speaking it.
lethalfang
Professional
Lotsa luck there...it took me 2 years to pass algebra (geometry is MUCH easier) and I'll tell you what....I've never ever used it...I do not care what
x =........it should be abolished...along with those, "two trains leave different stations at the same time" problems....Hey, I know..let's ban math period!!!
Are you the President by any chance?
xtremerunnerars
Hall of Fame
Post problems you have trouble with and someone (I'll help when it's something I know) will help you out.
Mastermind
Rookie
LMFAO @ lethal fang.
To the OP: if you can type it down I can probably help you, algebra isn't hard and I've taken Calculus.
To the OP: if you can type it down I can probably help you, algebra isn't hard and I've taken Calculus.
diegaa
Hall of Fame
LMFAO @ lethal fang.
To the OP: if you can type it down I can probably help you, algebra isn't hard and I've taken Calculus.
ditto, it has happened before.
i had 2 courses of algebra and 3 calculus. I almost dont recall anything, but like mastermind said, it isnt that hard.
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xtremerunnerars
Hall of Fame
Exactly: it's all relative. What's hard for you at age 11 is a joke when you're 18. I never really got how most tests could be hard because a lot of stuff you know it or you dont. Some things take a while and others demand a lot, but there's a pretty solid correlation between less intelligent people and how much they say stuff is hard.
Be glad if stuff comes naturally!
Wow, did you skip a grade or two? Because I'm a junior taking AP Calc, no sophomores at all.
By the way, did you start derivatives and limits? So far, Calc has been easy (can't say the same for the teacher).
And to the OP, algebra isn't really hard. Write down the problem and I'll try to help you with it (if I remember).
Naw AP Calc is nothing, well now, last year it was very hard
Though I had a much harder time with Geometry than anything I have had afterwards. Oh and AP US History is just insane. I hate it so much.....Yeah, I took it as a sophomore too, and I'm not like a genius or anything lol. Must just be what school you're in, because here AP Calc as a sophomore is for the pretty damn smart kids, but it's not like super unusual.
bluestreak711
Rookie
Two missing factors
3x+4y=1
2x+2y=1
and for future reference how would i type brackets
bluestreak711
Rookie
i searched for this specific kind of problem and it just returned two results
Two missing factors.
and i don't have a use for algebra unless i do take triginomitry or physics
beacsue when that is learned you can apply equations to tennis
and if all works well that is what i'll do
p.s. if i don't need but one between trig and physics i won't take but one
Court_Jester
Hall of Fame
Multiply the 2nd eqtn by -2 and you'll get the ff:
3x + 4y = 1
-4x -4y = -2
Add the two equations together to solve for x:
-x = -1
or
x = 1
Using this value for x, substitute this in either of the first two equations to solve for y (I'll use the 1st one):
3(1) + 4y = 1 => 4y = -2
or
y = -1/2
Solving systems of linear equations is so easy!
bluestreak711
Rookie
Multiply the 2nd eqtn by -2 and you'll get the ff:
3x + 4y = 1
-4x -4y = -2
Add the two equations together to solve for x:
-x = -1
or
x = 1
Using this value for x, substitute this in either of the first two equations to solve for y (I'll use the 1st one):
3(1) + 4y = 1 => 4y = -2
or
y = -1/2
Solving systems of linear equations is so easy!
ouch idk if i got a bit of that but my work book went from a problem like
5x+7=8x+4
5x-5x+7-4=8x+4-4-5x
7-4=8x-5x
3=3x
3.....3x
- = .. -
3......3
1=x
to something like that last problem and i am lost
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Court_Jester
Hall of Fame
Just messin' with ya! This happens to be one of my favorite math topics when I was in high school.
You did this one correctly, for what it's worth.
tennishead93
Semi-Pro
gifted geometry sux
bluestreak711
Rookie
well i didnt mean the problem i just did that i finally got that but the one with two equations i didnt understand a word
Court_Jester
Hall of Fame
Oh,...
That problem you listed is what is called system of linear equation. There is a solution if the number of unknown variables (here, x and y) is equal to the number of equations given. The trick is to multiply one of the equations by a number so that when you add it to another one, one of the variables will be eliminated, thus simplifying the system to the point that you can solve for remaining variable.
Tennis_Gnat
Rookie
Well......let's put it this way.
the 8x and the 5x are numbers that can be added and subtracted. Same with the 4 and the 7. you CANNOT add/subtract say 4 with 8x.
You want to solve for x. You want x to stand alone. So you need to combine the x terms.
It's also easier if you combine the non-x terms.
personally i think the way that's put is a bit confusing this is what i would write:
5x + 7 = 8x +4
5x goes across the river and changes signs (or gets subtracted off both sides....)
5x - 5x = 8x -5x + 4
OR (same thing, whichever makes more sense to you)
7 = 8x + 4 - 5x
(7 = 8x - 5x + 4)
7= 3x + 4
now the 4 goes across the river and changes signs
7-4 = 3x
3 = 3x
3/3 = x
1 = x
Now I feel intelligent again. thanks.
the 8x and the 5x are numbers that can be added and subtracted. Same with the 4 and the 7. you CANNOT add/subtract say 4 with 8x.
You want to solve for x. You want x to stand alone. So you need to combine the x terms.
It's also easier if you combine the non-x terms.
personally i think the way that's put is a bit confusing this is what i would write:
5x + 7 = 8x +4
5x goes across the river and changes signs (or gets subtracted off both sides....)
5x - 5x = 8x -5x + 4
OR (same thing, whichever makes more sense to you)
7 = 8x + 4 - 5x
(7 = 8x - 5x + 4)
7= 3x + 4
now the 4 goes across the river and changes signs
7-4 = 3x
3 = 3x
3/3 = x
1 = x
Now I feel intelligent again. thanks.
bluestreak711
Rookie
Go on........
Alright, let's look at your two equations.
3x+4y=1
2x+2y=1
The idea is to find a common factor for your X and Y values. Y was solved for you earlier and the Y values have a common factor of 4. What is the common factor for X? 6 is the common factor for X because 3x and 2x are multiples of 6. Let's pretend you don't know that Y is equal to -1/2 and lets try to eliminate the X from both equations. 3x+4y=1 becomes 6x+8y=2. 2x+2y=1 becomes 6x+6Y=3. Remember that 6 is the common factor for X, so we multiply everything in the first equation by 2 and everything in the second equation by 3. Now that both equations have 6x, we can subtract the two equations and eliminate the X variable.
''' 6x+8y=2 (ignore the '''. It won't space properly unless I use them)
- 6x+6y=3
____________
2y=-1
divide the 2 and you get y=-1/2. Then you can plug that into your original first equation and you'll get 3x+4(-1/2)=1. That becomes 3x-2=1. Add two to the other side and you get 3x=3. Divide the 3 to isolate the x and you get x=3/3 which is x=1. It's pretty hard to show this online. Go ask someone to show you in person. Once you get the hang of it, it is really easy.
Court_Jester
Hall of Fame
Let's take the problem you listed earlier:
3x + 4y = 1
2x + 2y = 1
You have a choice here, whether you want to eliminate the x first or the y. The question is how can we eliminate one of them. Let's say that we want to get rid of y first. Simply adding the two equations will not eliminate the y variable. However, if we multiply the 2nd equation by -2, the two equations will look like this:
3x + 4y = 1
-4x - 4y = -2
Note that any multiplier number other than -2 will not eliminate the y variable after adding the two equations. Now, by adding the two equations, note that the terms containing y will cancel out, leaving you with one equation with one unknown, the x variable.
3x - 4x + 4y - 4y = 1 - 2
or
-x = -1
You have now reduced the system of two linear equations to a single equation with one unknown, which can then be solved easily to give:
x = 1
Now that you have the value for x, substitute this value into either one of the original equations and you'll be able to solve for thte y variable. As a check, substitute the x and y values that you have obtained into any one of the equations. The value of the left hand side should equal the one on the right hand side.
Hope this clears it up.
3x + 4y = 1
2x + 2y = 1
You have a choice here, whether you want to eliminate the x first or the y. The question is how can we eliminate one of them. Let's say that we want to get rid of y first. Simply adding the two equations will not eliminate the y variable. However, if we multiply the 2nd equation by -2, the two equations will look like this:
3x + 4y = 1
-4x - 4y = -2
Note that any multiplier number other than -2 will not eliminate the y variable after adding the two equations. Now, by adding the two equations, note that the terms containing y will cancel out, leaving you with one equation with one unknown, the x variable.
3x - 4x + 4y - 4y = 1 - 2
or
-x = -1
You have now reduced the system of two linear equations to a single equation with one unknown, which can then be solved easily to give:
x = 1
Now that you have the value for x, substitute this value into either one of the original equations and you'll be able to solve for thte y variable. As a check, substitute the x and y values that you have obtained into any one of the equations. The value of the left hand side should equal the one on the right hand side.
Hope this clears it up.
Court_Jester
Hall of Fame
bluestreak711,
ffrpg offers an alternative solution. In his case, he chose to eliminate the x variable first (I chose the y). As you can see, we both came up with the same solution.
ffrpg offers an alternative solution. In his case, he chose to eliminate the x variable first (I chose the y). As you can see, we both came up with the same solution.
bluestreak711
Rookie
cool i think i got it
now all i gotta do is practice similar equations for a couple weeks and go on to the next step
so i will be back that is for sure
and by the way
the only person i know that can show me in person showed me
how to solve the equation=equation
with one variable on each side
but after i showed him the next step he didnt have a clue(the one yall just showed me that is)
anyway wish me luck
too bad i didnt get this much help when i post a thread on my tennis game
now all i gotta do is practice similar equations for a couple weeks and go on to the next step
so i will be back that is for sure
and by the way
the only person i know that can show me in person showed me
how to solve the equation=equation
with one variable on each side
but after i showed him the next step he didnt have a clue(the one yall just showed me that is)
anyway wish me luck
too bad i didnt get this much help when i post a thread on my tennis game
Duzza
Legend
Wow....I did that in my head mate, come on! Give us something harder!
Here's another easy one for you, Duzza.......
What's the value of (1-i)^12, where i is the sqrt(-1)?
Let's see you expand that in your head
lorenza
Semi-Pro
Here's another easy one for you, Duzza.......
What's the value of (1-i)^12, where i is the sqrt(-1)?
Let's see you expand that in your head
umm -64? i was bored and that's what i got, but i might have messed up somewhere with my negatives
beernutz
Hall of Fame
www.algebra1.com
This is more helpful if you are actually using one of the textbooks related to this site but even if not there is some good stuff on them.
This is more helpful if you are actually using one of the textbooks related to this site but even if not there is some good stuff on them.
bluestreak711
Rookie
ok is this correct?
7x+10y=2
4x+8y=9
28x+40y=8
28x+56y=63
-16y=-55
-16y/-16=-55/-16
y=3.4375
7x+10(3.4375)=2
7x+34.375=2
7x+34.375-34.375=2-34.375
7x=-32.375
7x/7=-32.375/7
x=-4.625
don't forget to look for the negatives the symbol is sometimes hard to see it is this little dash -
oh by the way if ya think i did well give me a thumbs up
7x+10y=2
4x+8y=9
28x+40y=8
28x+56y=63
-16y=-55
-16y/-16=-55/-16
y=3.4375
7x+10(3.4375)=2
7x+34.375=2
7x+34.375-34.375=2-34.375
7x=-32.375
7x/7=-32.375/7
x=-4.625
don't forget to look for the negatives the symbol is sometimes hard to see it is this little dash -
oh by the way if ya think i did well give me a thumbs up
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Court_Jester
Hall of Fame
I was about to post that your x value should have been negative but it seems that you were able to edit it.
Good job! See how easy it is?
Two thumbs up!
Good job! See how easy it is?
Two thumbs up!
bluestreak711
Rookie
I was about to post that your x value should have been negative but it seems that you were able to edit it.
Good job! See how easy it is?
Two thumbs up!
thanks yea i did it right on paper but when i type it to the pc i always mistype something
i most of the time and get in a hurry and type oyu instead of you
but i'll be back for sure so stay subscribed to this thread please
J-man
Hall of Fame
LOL that would be nice.Lotsa luck there...it took me 2 years to pass algebra (geometry is MUCH easier) and I'll tell you what....I've never ever used it...I do not care what
x =........it should be abolished...along with those, "two trains leave different stations at the same time" problems....Hey, I know..let's ban math period!!!
Duzza
Legend
Here's another easy one for you, Duzza.......
What's the value of (1-i)^12, where i is the sqrt(-1)?
Let's see you expand that in your head
Come on...I don't do complex numbers.....anymore.
Thanks for popping my expanding head though
.
dave333
Hall of Fame
yes, we haved dived into the world of derivitives, limits, and other stuff...
as for geometry, yeah, i hated geometry. So I skipped it. So happy i did it, cause we had to do formal proofs.
I took algebra II and either got sleep or did my homework while my teacher blabbed on.
I skipped pre-cal cuz my parents told me to.
lol, I was confused by what you were trying to ask. Never really seen it mentioned as Two missing factors, plus the reference to brackets didn't help.
jasoncho92
Professional
Ive never heard of a school that just let you skip math courses just because you want to lol. And alg 1 was incredibly easy lol. I literally slept through most classes because i had it first period and i aced it easily lol. But what ap cal are you taking? AB or BC?
bluestreak711
Rookie
ok need help again
1/2x+1/3y=2
x-1/3y=1
1/2x+1/3y=2
x-1/3y=1
bluestreak711
Rookie
and another one
x-3y=7
2x-2y=18
x-3y=7
2x-2y=18
ok need help again
1/2x+1/3y=2
x-1/3y=1
add the 2 equations together
1/2x + 1/3y = 2
1x - 1/3y = 1
-----------------
(1/2+1)x + (1/3 - 1/3)y = 2+1
1.5 x = 3
x = 2
either do substitution
x - 3y = 7 => x = 7 + 3y
so 2x - 2y = 18 => 2(7+3y) - 2y = 18
or multiple first equation by -2
-2*(x - 3y = 7) => -2x + 6y = - 14
then add the two equations together
-2x + 6y = -14
2x - 2y = 18
----------------
(-2 + 2)x + (6 - 2)y = -14 + 18
bluestreak711
Rookie
i didnt get a bit of that
bluestreak711
Rookie
both of them
i was taught to find common factors in the equations then subtract
then solve for a variable then plug it in to the first equation the gon on and solve for the last variable
i was taught to find common factors in the equations then subtract
then solve for a variable then plug it in to the first equation the gon on and solve for the last variable
bluestreak711
Rookie
it might sound like i know what i am talking about but i half do and half dont
im lost
im lost
