Discussion in 'Stringing Techniques / Stringing Machines' started by BigEleven, May 22, 2012.
How many feet of string does it need for K90 main and cross respectively?
I use 33 feet of synthetic gut to string my BLX90. I measure the short side at 9 feet. When it's all said and done, I'm left with about 1 to 1.5 feet on both sides, which is plenty to pull tension and tie off. By using 33 feet each time, I'm able to equally divide out a full reel of string without having to waste any. 660/33=20
That would depend on the string, stringer, and tension used.
And if you are using a drop weight with a rotary gripper 1' may not be enough to pull tension unless you have a starting clamp.
EDIT: I would suggest you start with 36' with a 10' short side and measure the exact length you need for yourself. Better safe than sorry.
Not correct. I have a linear pull dropweight and if it was rotary, it would take even less. The detailed aspect is that you're left with over a foot of string on both sides after the last pull. That's more than enough to pull tention, tie off, etc... way more than enough.
Thank you guys for the quick reply! I am going to do a 2-piece job on the racket with poly/poly hybrid on a stringer with a linear gripper. I will try 18 feet x 18 feet first and see what exactly is needed
That should be enough string. The poly will stretch less than the SG but 18' should be enough. That only leave you 9' for each side, I would try 19' for the mains. I like to have a little more string to work with when I tie poly string also.
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