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Reload this Page Who will challenge Federer 8 times this year?
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Old 03-03-2013, 07:38 PM   #1
NEW_BORN
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Default Who will challenge Federer 8 times this year?

I found it interesting that in the last 2 seasons, Federer has played a player 8 times during the course of the season.
2011 it was Tsonga, 6-2 in Fed's favor, then 2012 it was Del Potro, again 6-2 in Fed's favor.

So who will be the player this year to challenge Fed 8 times or more?
What will the H-H look like?

So far, Davydenko is the only player to have played Fed twice this season (lost both times)
Will he run into Fed 6 more times this year?
Will he lose them all?

So much to ponder
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Old 03-04-2013, 03:54 AM   #2
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I dont think it will be one of the big 4 or 5-8 ranked players given Fed's reduced schedule.

I will be surprised if Fed faces more than 5 times anyone in this year. And that will probably be Djokovic by sheer coincidence in the "draws".
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Old 03-04-2013, 04:07 AM   #3
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Everytime I look up, it seems like he's either playing Berdych, Del Potro, Murray, or Djokovic so one of those 4.
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Old 03-04-2013, 02:33 PM   #4
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Yeah i doubt it will be Murray or Djokovic, given that his current form will not carry him into the final stages of a tournament on a consistent basis.

I'm hoping that he plays some of the younger generation more often, which may also help to inspire him to carry on for a few more years.

I quite enjoy the prospect of a Fed-Tomic rivalry (a tactical matchup), not so much Fed-Dimitrov, because i think their style of aggressive play may be a little too similar for my liking.
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Old 03-05-2013, 06:07 AM   #5
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Berdytch 8 Federer 0?
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Old 03-05-2013, 02:12 PM   #6
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Berdytch 8 Federer 0?

If Fed plays Berdych 8 times this year, i think Berdych will win more than he loses, something like 5-3. Fed will have an advantage i believe at Indian Wells, Madrid, Halle but that's only if he can close out the match
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