|
|||||||
| Register | FAQ | Members List | Calendar | Search | Today's Posts | Mark Forums Read |
![]() |
|
|
Thread Tools | Display Modes |
|
|
#41 |
|
Rookie
Join Date: Jun 2012
Posts: 135
|
Give me a couple of hours
|
|
|
|
|
|
#42 |
|
Rookie
Join Date: Jul 2009
Location: Arvada CO
Posts: 152
|
Thanks for posting all the good info. Here is what I got. I have tune my daughter's racquet (she is 15) for a long time using Travlerajm's method and it seem to work very well. I ended up with 324g with a balance of 32.7 and swingweight of 310. She was using a windsheild style forehand and it seemed that the shots where very spinny but not a lot of power. I tried all kinds of strings and tensions and I could not get any more power out of it. So we changed here swinging style to a Djokovic style swing which took about a month to do. Now that racquet will not work at all. The balls fly all over the place. No control at all. Tried more strings and no luck. So I tried another racquet. It was an nTour Wilson and it has some weird specs so it could be fake I don't know. Well she started hit a little better. So I just started adding lead to the top of the racquet and it got better and better and better. I added 18 grams at 12. So now her shots are controlled with a lot of spin and power. The specs are 314g with a balance of 34 and 337 swingweight. Not really close to the other specs. So I was just trying to figure out what is so different between the two styles of hitting and the curve on the racquet map. Here is a link for some WTA specs.
http://www.hdtennis.com/grs/pro_racq...ance-open.html Look at Sloane Stevens racquet. Thanks again. |
|
|
|
|
|
#43 |
|
Rookie
Join Date: Jun 2012
Posts: 135
|
What puzzles me is that the lighter Travlerajm racket has virtually the same MgR/I and the same shape of the curve. But if you add weight at the center of a racket, the shape of the curve also remains the same, but MgR/I increases.
|
|
|
|
|
|
#44 | |
|
Rookie
Join Date: Jun 2012
Posts: 135
|
Quote:
My guess is that with her old racket the rackethead was feeling light to her in relation to the static mass and balance. Resulting in high rackethead speed and thus easier spin, but less plow. Djokovic drives thru the ball flatter which would be harder to do when you don't feel enough weight in the rackethead. Last edited by JohnB : 09-12-2012 at 12:53 PM. |
|
|
|
|
|
|
#45 | |
|
Rookie
Join Date: Apr 2010
Location: Stockholm, Sweden
Posts: 213
|
Quote:
You can find other placements of the weight that might change the curve, but not MgR/I. For example you can add 10 kg at the but end or at a point around 48 cm without changing MgR/I. Last edited by stoneage : 09-15-2012 at 09:03 AM. |
|
|
|
|
|
|
#46 | |
|
Rookie
Join Date: Jun 2012
Posts: 135
|
Quote:
|
|
|
|
|
|
|
#47 | |
|
Rookie
Join Date: Jun 2012
Posts: 135
|
Quote:
One racket had all the added weight at the sides and the other one in a more polarized manner. The played very different despite having the same curve (and the same MgR/I). I am not only referring to ball trajectory, but also the felt racketheadcontrol. The polarized one has a whippier feel than the other one. The equivalent mass is the same for both rackets, but do you know why they play so different? I think I know why just by experience, but it would be great if there was a scientific explanation. |
|
|
|
|
|
|
#48 | |
|
Hall Of Fame
Join Date: Mar 2006
Posts: 4,043
|
Quote:
The higher twistweight frame has higher SW in the plane of your actual swing, so effective MgR/I is lower for that frame.
__________________
BLX Blade 98. 13.74oz., 12.55", 370.5 SW. Pre-Stretched Ashaway Kevlar 18g/Zyex Monogut Red 16g, 55 lbs |
|
|
|
|
| travlerajm |
| View Public Profile |
| Find More Posts by travlerajm |
|
|
#49 |
|
Semi-Pro
Join Date: Jul 2009
Posts: 630
|
Could you elaborate on what you mean by that? Perhaps a drawing would help.....
|
|
|
|
|
|
#50 | |
|
Hall Of Fame
Join Date: Mar 2006
Posts: 4,043
|
Quote:
Your actual swing occurs in a plane that is neither completely normal nor completely parallel to the stringbed, so the twistweight contributes to the "effective" swingweight, which is always slightly higher than the measured swingweight. In most cases, the difference between measured swingweight and "effective" swingweight is consistent enough that it is not worth worrying about the difference. But the example presented (with 2 frames of equal mass, balance, and measured SW, but different mass distributions) is a case where the difference does come into play. I have to go catch a plane this morning, so I'll leave a drawing to someone else.
__________________
BLX Blade 98. 13.74oz., 12.55", 370.5 SW. Pre-Stretched Ashaway Kevlar 18g/Zyex Monogut Red 16g, 55 lbs Last edited by travlerajm : 09-15-2012 at 09:23 PM. |
|
|
|
|
| travlerajm |
| View Public Profile |
| Find More Posts by travlerajm |
|
|
#51 | |
|
Semi-Pro
Join Date: Jul 2009
Posts: 630
|
Quote:
Also, isn't saying "In most cases, the difference between measured swingweight and "effective" swingweight is consistent enough that it is not worth worrying about the difference." a bit misleading? As you pointed out yourself - if you add weight to the sides of the racket the 'effective swingweight' actually changes apparently noticeably. Isn't adding weight to the sides of the racket like at least as common as adding the weight at the top or bottom of the racket? In other words 'most cases' is like 50% of the cases, no? Last edited by jmnk : 09-15-2012 at 09:50 PM. |
|
|
|
|
|
|
#52 |
|
New User
Join Date: Aug 2012
Posts: 50
|
whoever's a physics phd should write his dissertation on this stuff.
|
|
|
|
| spectastic |
| View Public Profile |
| Find More Posts by spectastic |
|
|
#53 | |
|
Rookie
Join Date: Apr 2010
Location: Stockholm, Sweden
Posts: 213
|
Quote:
![]() Some corrections and clarifications: The swing weight (Ix) is measured around an axis in the plane of the string bed (x-axis), not normal to it (but you probably mean that). The twist weight (Iy) is measured around an axis along the length of the racquet (y-axis) and affects the swing very little (but is important at an off-line impact). It is right that a normal swing not is entirely around the string bed plane and that the actual swingweight is a little higher. The moment of inertia (Iz) around the third axis is higher than the swingweight, which follows from perpendicular axis theorem Iz=Ix+Iy. However, in a racquet these two "swingweights" (Ix and Iz) are similar since Iy is small, so their combined effect from not swinging entirely around the x-axis is fairly small. An example: assume an evenly balanced racquet with a weight of 320 g, a swing weight (Ix) of 325 kg cm^2 and a twist weight (Iy) of 15 kg cm^2 ( a typical value). Using the the parallel axis and perpendicular axis theorems you get that Iz is 340 kg cm^2 . That is the swingweight if you swing with edge towards the ball (not so common). If you swing with racquet with the head tilted at some other angle it is much more complicated and you have to involve the products inertia as well. But assuming that the racquet is flat ( a fair assumption) you approximate the moment of inertia at an angle a with Ia = Ix*(cos a)^2+ Iz*(sin a)^2 if a is 45 degrees Ia becomes the average of the two. So the swingweight of a swing with the head at 45 degree angle is 332 or 2% higher. More importantly, this increase is almost the same for all racquets, so it is hardly worth bothering about. __________________________________________________ _________ racquetTune, stringBed and swingTool racquet apps for the iPhone/iPad. Last edited by stoneage : 09-16-2012 at 11:58 PM. |
|
|
|
|
|
|
#54 | |
|
Rookie
Join Date: Apr 2010
Location: Stockholm, Sweden
Posts: 213
|
Quote:
Last edited by stoneage : 09-16-2012 at 07:04 AM. |
|
|
|
|
|
|
#55 | ||
|
Semi-Pro
Join Date: Jul 2009
Posts: 630
|
Quote:
Quote:
But what I do not understand is whether in MgR/I equation one shall use: a) Ix (which is what is being published as 'swingweight')? or b) Ix + Iz (which would take into account twistweight as well)? Because in all previous threads and posts the only value ever mentioned or discussed was Ix. Now, when JohnB points out that two rackets with identical mass, balance, and swingweight (Ix) - which obviously means that MgR/I is also identical - do feel differently, travlerajm says that this is expected since the twistweight (Iy) of those two rackets is different. well, which is it than? Either 'I' in MgR/I is just Ix and you at least can claim you are using published specs to back up your claims. Or 'I' in MgR/I is 'Ix+Iy' and than the entire line of thinking backing up this MgR/I idea needs to be redone since: - no one measures Ix+Iy unless specifically told to do so, and - therefore people were tuning rackets to MgR/I=21.0 using incorrect value of I, and - there's no way to compare that to pro's racket specs since they do not publish Iy of pros rackets. |
||
|
|
|
|
|
#56 |
|
Rookie
Join Date: Jun 2012
Posts: 135
|
I am planning on a couple more experiments.
Namely, first I will up the swingweight enough of the polarized racket to match it to the effective swingweight of the higher twistweight racket and then compare. Second I will try to set-up both rackets, one more polarized than the other, but now not only with identical mass, balance and swingweight, but also with the same twistweight and then compare. |
|
|
|
|
|
#57 | |
|
Rookie
Join Date: Apr 2010
Location: Stockholm, Sweden
Posts: 213
|
Quote:
The twist weight is Iy, i.e. around the y-axis. The swing occurs mainly around the x and z axis, and is "controlled" by a combination of Ix and Iz, but since they are fairly similar the error by using only Ix, i.e. the swingweight, is small. So my first conclusion is: you can continue to use swingweight as before. The twistweight will affect the feel of the racquet, but it doesn't influence the swing that much and can therefore be treated as a separate problem. Still I think twistweight is a neglected parameter that is worth keeping an eye on. Some more about twist weight here: I am not going to comment on what to use in MgR/I since I don't know (I have yet to see a reasonable explanation how MgR/I influence a tennis swing). __________________________________________________ _________ racquetTune, stringBed and swingTool racquet apps for the iPhone/iPad. Last edited by stoneage : 09-17-2012 at 01:57 AM. |
|
|
|
|
|
|
#58 |
|
New User
Join Date: Sep 2012
Location: K'zoo
Posts: 4
|
@stoneage Thanks for your many technical posts. This is an interesting attempt to develop a new way of looking at the weight parameters of racquets.
However, I believe there is a mistake in the formula in your effective_mass.xlsx spreadsheet. There is an extra factor of 2 in the denominator there. When you take that out, the plots become monotonic with 15/r and you get much larger effective masses on the right side. In the eqv_mass_norm.xlsx spreadsheet, I don't understand the expression for the reference racquet that you use in the denominator there. Can you explain how Ip for the reference racquet equals 320 (1033 + 50*r + r*r) ? Using I[end] = (M*L^2)/3 for a uniform rod, I get Ip = 320 (70*70/3 + r*r) for the reference racquet. This makes the curves look quite different. Anyways, thanks for posting something that was motivating enough to get me to finally de-lurk! |
|
|
|
|
|
#59 |
|
Talk Tennis Guru
Join Date: Dec 2008
Posts: 22,130
|
When matching racket/weights to players, there is NO direct corelation between a certain fix and the player's ability to PLAY better. Too many X factors come to play.
|
|
|
|
|
|
#60 | ||
|
Rookie
Join Date: Apr 2010
Location: Stockholm, Sweden
Posts: 213
|
Quote:
Quote:
Ip=M*L^2/12+M*(c+r)^2 and c for an evenly balanced rod is L/2-10 = 25 so I get Ip=M*70*70/12+M*(25+r)^2= M*(1033+50*r+r*r) Also remember that the parallel axis theorem can only be used in relation to the MOI around the center of mass, so you can't calculate Ip the way you did, even if r would have been to the endpoint of the racquet. |
||
|
|
|
![]() |
|
||||||
| Thread Tools | |
| Display Modes | |
|
|