ATP Finals 2018 RR3: (3) Alexander Zverev vs (8) John Isner

Zverev or Isner?

  • Zverev in 2

    Votes: 3 25.0%
  • Zverev in 3

    Votes: 3 25.0%
  • Isner in 2

    Votes: 4 33.3%
  • Isner in 3

    Votes: 2 16.7%

  • Total voters
    12
  • Poll closed .
isner-2.jpg
 
"Zverev was brave"

Whatever crack Koenig is smoking, it needs to be off the streets. Kids are gonna die from that.
 
If Zverev wins this set, even in a tie-break, I believe Djokovic tops the group even if Cilic double bagels him. Street advances from 2nd place.
 
One too many I/O FH errors and Isner eliminates himself.

He’s not tanking to start the second set so Zedraffe won’t waltz into the SFs.
 
3 Sets for Zverev and Cilic is out too.

Cilic's only hope is Isner wins in 3 (now) and he beats Djoko (in 2 or 3)
I don't think so, if Zverev wins in 3 and Cilic wins in 2 you'll have:

1) Djokovic 2-1 4-2
Cilic 2-1 4-3
Zverev 2-1 4-3

So the percentage of games won would decide who advances - Cilic or Zverev. Djokovic tops the group if Zverev loses a set.

If Zverev wins like 7-6 6-7 6-3 and Cilic beats Djokovic 7-6 7-6 then Cilic is through.
 
I don't think so, if Zverev wins in 3 and Cilic wins in 2 you'll have:

1) Djokovic 2-1 4-2
Cilic 2-1 4-3
Zverev 2-1 4-3

So the percentage of games won would decide who advances - Cilic or Zverev. Djokovic tops the group if Zverev loses a set.
This means cilic will go through :unsure:
 
Isner the moral winner of the Edberg Sportsmanship award for shaking Zedraffe’s hand after the line clipper ace is called out.
 
I don't think so, if Zverev wins in 3 and Cilic wins in 2 you'll have:

1) Djokovic 2-1 4-2
Cilic 2-1 4-3
Zverev 2-1 4-3

So the percentage of games won would decide who advances - Cilic or Zverev. Djokovic tops the group if Zverev loses a set.

If Zverev wins like 7-6 6-7 6-3 and Cilic beats Djokovic 7-6 7-6 then Cilic is through.
I thought so first but because Zverev and Cilic will be tied on set percentages (and not Djokovic), it goes to h2h between Zverev and Cilic, and Zverev progresses.

From https://www.nittoatpfinals.com/en/event/semifinal-qualifying-procedure

"Comment 4: 3 players have 2 wins and the other player has 0 wins. The player with 0 wins is eliminated. Of the 3 players with 2 wins, 1 player’s sets won-loss is 5-2 for 71.43%; the other 2 players both have a 4-3 record in sets for 57.14%. In this case there is 1 superior player (71.43%) and the remaining 2 players are tied; it now reverts to the head to head result of the 2 remaining players with the winning player advancing as group runner-up."
 
I don't think there's any way Djokovic can't top the group. The worst case scenario is that Zverev beats Isner 7-6 6-4 and Cilic wins 6-0 6-0.

In this case:
1) Djokovic 2-1 4-2 24-24
2) Zverev 2-1 4-2 39-40
3) Cilic 2-1 4-3 42-28
 
Zverev serving the best I have seen him serve. This could be a turning point if he continues to serve this well next year.
 
I don't think so, if Zverev wins in 3 and Cilic wins in 2 you'll have:

1) Djokovic 2-1 4-2
Cilic 2-1 4-3
Zverev 2-1 4-3

So the percentage of games won would decide who advances - Cilic or Zverev. Djokovic tops the group if Zverev loses a set.

If Zverev wins like 7-6 6-7 6-3 and Cilic beats Djokovic 7-6 7-6 then Cilic is through.
It's no longer a three way tie because Djokovic's set win-loss is superior to both of theirs. It would come down to who won the meeting between Zverev and Cilic.
 
This is confusing:mad:
A three way tie is when you have 3 players who went 2-1 in matches and have the same percentage of sets won (like 4-2). Then you look at games and decide who goes through based on that. In our case we won't have 3 players with the same percentage of sets won, Djokovic is already at an an advantage because he's currently 4-0 so can't do worse than 4-2 and Cilic is at a disadvantage because he's currently at 2-3.
 
A three way tie is when you have 3 players who went 2-1 in matches and have the same percentage of sets won (like 4-2). Then you look at games and decide who goes through based on that. In our case we won't have 3 players with the same percentage of sets won, Djokovic is already at an an advantage because he's currently 4-0 so can't do worse than 4-2 and Cilic is at a disadvantage because he's currently at 2-3.
I think I understand now :)
 
Now I'm wondering if there's a possibility that you have a player who went 2-1 in matches, doesn't qualify and the players he beat are those who did.

Edit: nah, impossible because the 4th player would have to get a win.
 
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Street wins 7-6 6-3. So now assuming Djokovic gets double bageled (LMAO):

1. Djokovic 2-1 4-2 24-24
2. Zverev 2-1 4-2 39-39
3. Cilic 2-1 4-3 42-28
4. Isner 0-3 1-6 36-50

Djokovic just has to show up LMAO. Looks like Djokovic-Cilic is a dead rubber given how Cilic can't qualify and Djokovic advances from first place even if he gets double bageled.
 
GSM Zverev, deserved win too and i think that means he's through to the SF right?

I'm just glad the boring serve-bot is out. Beaten by all 3 players in his group because he doesn't belong here. One trick-pony players don't belong in the world tour finals.
 
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