# How many pts HL is 325mm balance ??

#### MAXXply

##### Hall of Fame
My standard length (70cm) racket has this balance - how many points headlight does 325mm translate to ? The balance point seems to be immediately under the 6 o'clock position (i.e the underside of the hoop) and I'm really liking it.
To beef up my lightweight 287gm racket, what are some suitable lead placements that won't alter this balance too much? Thanks for any advice.

#### aphex

##### Banned
27 inches is not 70cm. it's 68.58cm.

68.58/2=34.29

34.29-32.5=1.79

1.79/2.54=0.7047

0.7047*8=5.64

#### charliefedererer

##### Legend
27 inches is not 70cm. it's 68.58cm.

68.58/2=34.29

34.29-32.5=1.79

1.79/2.54=0.7047

0.7047*8=5.64

My problem with higher mathematics is that it is all Greek to me.

#### PimpMyGame

##### Hall of Fame
Is the 325mm an unstrung balance? From your description it sounds like your actual balance is closer to even. But I'm struggling to visualise and I don't have a racket to hand.

#### Irvin

##### Talk Tennis Guru
27 inches is not 70cm. it's 68.58cm.

68.58/2=34.29

34.29-32.5=1.79

1.79/2.54=0.7047

0.7047*8=5.64

It appears math is all Greek to 'aphex' too. Pun intended. lol Sorry I could not resist.

Irvin

#### MAXXply

##### Hall of Fame
27 inches is not 70cm. it's 68.58cm.

68.58/2=34.29

34.29-32.5=1.79

1.79/2.54=0.7047

0.7047*8=5.64

#### Gee

##### Hall of Fame
My problem with higher mathematics is that it is all Greek to me.
Charlie,

Here I 'll try to explain the algorithm into 3 steps.

How to convert balance point from cm into HL points
• First determine the even balance point. Simply divide the racquet length by 2. Notice this is equal to 0 points HL/HH.
68,58 cm / 2 = 34,29 cm
• Determine the distance between the even balance point and the actual balance point. Subtract the actual balance point (into cm) from the even balance point
34,29 cm - 32,5 cm = 1,79 cm
• Convert the result (from cm) into HL points. (Note: 1 point = 1/8 inch and 1 inch = 2,54 cm). First convert the result from cm into inches and then multiply by 8.
(1,79 / 2,54) * 8 = 5,64

I hope it is clear to you!

Last edited:

#### MAXXply

##### Hall of Fame
Is the 325mm an unstrung balance? From your description it sounds like your actual balance is closer to even. But I'm struggling to visualise and I don't have a racket to hand.

No, it's listed on the racket as the strung balance. It's the 100sq.in Dunlop Rapid 270 - pictured on the TW Europe page. Visualise an AG 500 but in an even lighter, more HL racket. Dunno why Dunlop didn't slot this in its Aerogel line-up as a lightweight midplus option - instead they included the relatively granny sized 105sq.in models.

#### PimpMyGame

##### Hall of Fame
No, it's listed on the racket as the strung balance. It's the 100sq.in Dunlop Rapid 270 - pictured on the TW Europe page. Visualise an AG 500 but in an even lighter, more HL racket. Dunno why Dunlop didn't slot this in its Aerogel line-up as a lightweight midplus option - instead they included the relatively granny sized 105sq.in models.

ok. If that racket is anything like an Evo 270 I hear that's a pretty nice cheaper stick.

#### MAXXply

##### Hall of Fame
ok. If that racket is anything like an Evo 270 I hear that's a pretty nice cheaper stick.

Yes - it's just the updated cosmetic from the EVO 270. Gonna lead it up a bit though.

#### Kingv

##### New User
in Centimeters...

68.58 / 2 = 34.29

34.29 - 32.5 = 1.79

1.79 / 0.3175 = 5.63 HL

(0.3175 = 1/8")

ok