How many pts HL is 325mm balance ??

[MAXXply]

My standard length (70cm) racket has this balance - how many points headlight does 325mm translate to ? The balance point seems to be immediately under the 6 o'clock position (i.e the underside of the hoop) and I'm really liking it.
To beef up my lightweight 287gm racket, what are some suitable lead placements that won't alter this balance too much? Thanks for any advice.

 

[aphex]

27 inches is not 70cm. it's 68.58cm.

68.58/2=34.29

34.29-32.5=1.79

1.79/2.54=0.7047

0.7047*8=5.64


your racquet is 5.64 points headlight.

 

[charliefedererer]

27 inches is not 70cm. it's 68.58cm.

68.58/2=34.29

34.29-32.5=1.79

1.79/2.54=0.7047

0.7047*8=5.64


your racquet is 5.64 points headlight.

My problem with higher mathematics is that it is all Greek to me.

 

[PimpMyGame]

Is the 325mm an unstrung balance? From your description it sounds like your actual balance is closer to even. But I'm struggling to visualise and I don't have a racket to hand.

 

[Irvin]

27 inches is not 70cm. it's 68.58cm.

68.58/2=34.29

34.29-32.5=1.79

1.79/2.54=0.7047

0.7047*8=5.64


your racquet is 5.64 points headlight.

It appears math is all Greek to 'aphex' too. Pun intended. lol Sorry I could not resist.

Irvin

 

[MAXXply]

27 inches is not 70cm. it's 68.58cm.

68.58/2=34.29

34.29-32.5=1.79

1.79/2.54=0.7047

0.7047*8=5.64

your racquet is 5.64 points headlight.

My bad...thank you

 

[Gee]

My problem with higher mathematics is that it is all Greek to me.

Charlie,

Here I 'll try to explain the algorithm into 3 steps.

How to convert balance point from cm into HL points

• First determine the even balance point. Simply divide the racquet length by 2. Notice this is equal to 0 points HL/HH.

68,58 cm / 2 = 34,29 cm​

• Determine the distance between the even balance point and the actual balance point. Subtract the actual balance point (into cm) from the even balance point

34,29 cm - 32,5 cm = 1,79 cm​

• Convert the result (from cm) into HL points. (Note: 1 point = 1/8 inch and 1 inch = 2,54 cm). First convert the result from cm into inches and then multiply by 8.

(1,79 / 2,54) * 8 = 5,64

​

I hope it is clear to you!

 

[MAXXply]

Is the 325mm an unstrung balance? From your description it sounds like your actual balance is closer to even. But I'm struggling to visualise and I don't have a racket to hand.

No, it's listed on the racket as the strung balance. It's the 100sq.in Dunlop Rapid 270 - pictured on the TW Europe page. Visualise an AG 500 but in an even lighter, more HL racket. Dunno why Dunlop didn't slot this in its Aerogel line-up as a lightweight midplus option - instead they included the relatively granny sized 105sq.in models.

 

[PimpMyGame]

No, it's listed on the racket as the strung balance. It's the 100sq.in Dunlop Rapid 270 - pictured on the TW Europe page. Visualise an AG 500 but in an even lighter, more HL racket. Dunno why Dunlop didn't slot this in its Aerogel line-up as a lightweight midplus option - instead they included the relatively granny sized 105sq.in models.

ok. If that racket is anything like an Evo 270 I hear that's a pretty nice cheaper stick.

 

[MAXXply]

ok. If that racket is anything like an Evo 270 I hear that's a pretty nice cheaper stick.

Yes - it's just the updated cosmetic from the EVO 270. Gonna lead it up a bit though.

 

[Kingv]

in Centimeters...

68.58 / 2 = 34.29

34.29 - 32.5 = 1.79

1.79 / 0.3175 = 5.63 HL

(0.3175 = 1/8")

 

[dainova]

ok