Find the point to which the origin must be translated in order that the transformed equation will be of a circle at (0,0). Equation is: (x-1.79)^2 + (y-1.93)^2 = 4.33 Procedure would be appreciated. Cheers!

Trolling? That equation is of a circle centered at (1.79,1.93). Where do you think the origin should be moved?

The origin is at (0,0). The problem is to translate the origin to the center of the circle given by the equation. The center of the circle given by the equation is (1.79, 1.93). BTW, the radius of the circle is the square root of 4.33. The equation (x-a)^2 + (y-b)^2 = c^2 is a circle with center (a, b) and radius c.

My son tutored at his university for four years in Calc 1, 2, 3, Physics, Chemistry, Biology, Logic Design, Differential Equations, Linear Algebra, Discrete Mathematics, Algorithms and Economics. Every once in a while, someone would come in with a take-home test and ask him to go through the problems. Answering a question isn't a problem as presumably a bunch of similar problems are assigned so the student just needs a general idea on how to solve the problem. Physics Forums is a better place to go for math and physics homework help.

^^^Honestly, no, it usually is not. People on physics forums tend to be rather...pretentious if you don't get a concept. I used them a lot during freshman engineering for calc 1 and 2. Typical responses were "are you sure you went to class? That should have been covered in the first week." Having been a math and engineering tutor myself and understanding how most kids think (aka if they didn't get it in lecture, they likely won't get it if someone lectures them), your son's approach is best. Going through a similar problem step by step showing them what each of the parts means and how to use them does wonders. They can then do their own problem with the tutor and try to apply the concepts they just finally had "click".

Well, that's my approach too (he was home-schooled). The physics forum doesn't want to give out answers. It assumes some level of competence and takes a Socratic approach to lead you to the answer. If you are not up on what is going on - then that doesn't work well. Yes, math, physics and computer science folks can be a little difficult but they usually take it down a notch if you're not getting it. Taking it step-by-step works well if you can assess but that's a lot harder to do online than in-person.

Well, then why even enter the thread? Have you ever realized that some people may need help, as it is in my case? I also stated that if you could write down the procedure, it would be appreciated. If I wanted to cheat, I would not ask for procedure. I asked so I could understand my failures. /Rant.