SpinToWin
Talk Tennis Guru
So I thought I'd make a thread about how different shaped strings' gauges are measured and what this means relative to a regular round string.
Now, there are two assumptions I will make in order to make the calculations possible and more simple:
1) the gauge is 1.25mm.
2) The shape is that of a regular polygon.
I will calculate a few values:
Since we're discussing regular polygons, this is a equilateral triangle. The only sensible value for the gauge seems to be the altitude of the string (h in the diagram below):
By making h=1.25mm, we get values of a=b=c=1.443mm (pythagoras). Now, if this triangle was inscribed in a circle, the lines from the centre to the corners of the triangle are congruent (and all radii) and thus form similar triangles:
Using this geometric property, I can use the sin rule to find the radius of the circle in which the triangle is inscribed:
r=0.83333mm, which means that the diameter is 1.667mm!
Of course, the string doesn't play nearly that thick, so let's move on to the areas…
The area of a circle with a 1.25mm diameter = 1.227mm^2.
The area of a triangle with an altitude of 1.25mm = 0.902mm^2.
What would the gauge of a round string have to be to have the same area? 1.07mm!
Square shaped strings:
Of course, the first problem we face here is how is the gauge of this string measured? Is it the altitude or is it the diagonal? I will analyze both scenarios, though I put my money on the gauge being measured on the flat edges (a lot easier), so the altitude seems to be the better value (in general for polygons with an even number of sides).
Having said that, let's start out with the diagonal being the gauge:
If the diagonal has a length of 1.25mm, then the side length is 0.8839mm. Obviously, the diameter of the circle in which this square is inscribed = 1.25mm (it is the diagonal).
Essentially, we get an area of 0.78125mm^2 for the square (1.227mm for circle).
For a round string to have the same area, its gauge would have to be 0.997mm!
Next let's take the more realistic case where the gauge is the altitude ( = side length a in the diagram below) of the square.
In that case, the diameter of the circle encompassing the square is 1.768mm!
The area of the square is 1.5625mm^2 (1.227mm for circle).
For the round string to have the same area, it would have to have a 1.41mm gauge!
Pentagonal shaped strings:
As with any polygon with an odd number of sides/corners, there is really only one way to measure the gauge, and that is the altitude.
Now, the calculations here are slightly more complicated, but I got the following values:
The diameter of the encompassing circle is 1.382mm.
The area of the pentagon is 1.135mm^2 (relative to 1.227mm^2 for a round string with the same gauge).
For a round string to have the same area, its gauge would have to be 1.202mm.
Hexagonal shaped strings:
Once again there are two possibilities to measure the gauge, using the altitude or the diagonal.
Let's start with the diagonal:
As you can see, the diagonal equals the diameter of the circumscribing circle (1.25mm). The area of the hexagon = 1.015mm^2 (circle 1.227mm^2). For a circle to have the same area as the hexagon, its diameter would have to be 1.137mm.
Next is the altitude:
In this case, the diameter of the circumscribing circle would be 1.443mm. The area of a hexagon with a 1.25mm gauge in this sense is 1.353mm^2 (1.227mm^2 circle). For a circle to have the same area, it would have to have a diameter of 1.313mm.
Heptagonal shaped strings:
Again, here there's only one way to measure the gauge, namely the altitude:
The diameter of the circumscribing circle here is 1.315mm.
The area of the heptagon is 1.183mm^2 (1.227mm^2 circle).
For a circle to have the same area, its diameter would have to be 1.227mm.
Octagonal shaped strings:
Gauge measured as diagonal:
Diameter of circumscribed circle = diagonal = 1.25mm.
Area of octagon = 1.105mm^2 (1.227mm^2 circle).
Diameter of a circle with the same area = 1.210mm.
Gauge measured as height (A):
Diameter of circumscribing circle = 1.353mm.
Area of octagon = 1.294mm^2 (1.227mm^2 circle).
Diameter of circle with the same area = 1.284mm.
Conclusion:
Now let us sum up what we found, however, using only values with altitudes as measures for the gauge size (simply because this seems like the more realistic assumption). In case you know there is an exception, you can refer to the other values above for guidance
First is a graph, with the amounts of sides of the polygon as the x-axis and the diameter of the circumscribing circle as the y-axis. At first it seems like there is no relationship. However! If you isolate odd and even sided polygons respectively, you will find that the two data sets correlate in a similar way (what seems to be two negative regressive exponential functions, only vertically/horizontally translated). Essentially, the less sides a shape has, the further the maximum distance from the center point to the edges is. However, shapes with even numbers of sides have a relatively higher maximum displacement relative to shapes with odd numbers of sides.
Conclusions:
1) Among odd/even sided strings, those with less sides will feel thicker.
2) For sides with close numbers of sides, even sided shapes will feel thicker.
The next diagram has the amounts of sides of the polygon as the x-axis and the gauge of a round string for which the cross sectional area is equal to that of a 1.25mm shaped string as the y-axis. Here too we can split odd and even sides and find interesting results. Odd sided strings show a positive regressive relationship, whereas even shaped strings show a negative regressive relationship and are always above the level of odd shaped strings! Additionally, it seems like both curves are approaching the regular gauge of the round string (1.25mm), so it seems like that may be a asymptote the two curves approach as they get more and more sides.
Conclusions:
1) Strings with odd numbers of sides have a thinner equivalent gauge than those with even side numbers.
2) The more sides a odd sided string has, the thicker its equivalent gauge is.
3) The more sides a even sided string has, the thinner its equivalent gauge is.
4) Shaped strings with odd numbers of sides have a lower equivalent gauge than comparable round strings.
5) Shaped strings with even numbers of sides have a higher equivalent gauge than comparable round strings.
Thoughts:
The most interesting statistical outlier here is the square shaped string, for its shape takes up the most space (measured as a circumscribing circle, which is the grommet hole shape), and it has by far the highest cross sectional area relative to its gauge. Due to this it is reasonable to suggest that these strings will feel considerably thicker than other shapes (at the same gauge) and that they will be heavier due to their added cross sectional area. Very stiff offerings of these strings are likely to play relatively more uncomfortable and should be treated carefully.
Furthermore, this data seems to suggest that strings with odd numbers of sides play relatively thin, whereas strings with even numbers of sides play relatively thick.
It is entirely possible that these values influence our perception of liveliness and ball feel, which we often attribute to thinner gauges of round strings.
Questions for you: What (other) kinds of implications could these numbers have, and are there any other values that should be calculated?
Now, there are two assumptions I will make in order to make the calculations possible and more simple:
1) the gauge is 1.25mm.
2) The shape is that of a regular polygon.
I will calculate a few values:
- The gauge of a circle (round string) into which the shape is inscribed.
- The area of the shaped string with this gauge relative to a round string with the same gauge (if necessary, using different axes along which this gauge is measured)
- The gauge a round string would have in order to have the same area as the shaped string
Since we're discussing regular polygons, this is a equilateral triangle. The only sensible value for the gauge seems to be the altitude of the string (h in the diagram below):

By making h=1.25mm, we get values of a=b=c=1.443mm (pythagoras). Now, if this triangle was inscribed in a circle, the lines from the centre to the corners of the triangle are congruent (and all radii) and thus form similar triangles:
Using this geometric property, I can use the sin rule to find the radius of the circle in which the triangle is inscribed:
r=0.83333mm, which means that the diameter is 1.667mm!
Of course, the string doesn't play nearly that thick, so let's move on to the areas…
The area of a circle with a 1.25mm diameter = 1.227mm^2.
The area of a triangle with an altitude of 1.25mm = 0.902mm^2.
What would the gauge of a round string have to be to have the same area? 1.07mm!
Square shaped strings:
Of course, the first problem we face here is how is the gauge of this string measured? Is it the altitude or is it the diagonal? I will analyze both scenarios, though I put my money on the gauge being measured on the flat edges (a lot easier), so the altitude seems to be the better value (in general for polygons with an even number of sides).
Having said that, let's start out with the diagonal being the gauge:

If the diagonal has a length of 1.25mm, then the side length is 0.8839mm. Obviously, the diameter of the circle in which this square is inscribed = 1.25mm (it is the diagonal).

Essentially, we get an area of 0.78125mm^2 for the square (1.227mm for circle).
For a round string to have the same area, its gauge would have to be 0.997mm!
Next let's take the more realistic case where the gauge is the altitude ( = side length a in the diagram below) of the square.

In that case, the diameter of the circle encompassing the square is 1.768mm!
The area of the square is 1.5625mm^2 (1.227mm for circle).
For the round string to have the same area, it would have to have a 1.41mm gauge!
Pentagonal shaped strings:
As with any polygon with an odd number of sides/corners, there is really only one way to measure the gauge, and that is the altitude.

Now, the calculations here are slightly more complicated, but I got the following values:
The diameter of the encompassing circle is 1.382mm.
The area of the pentagon is 1.135mm^2 (relative to 1.227mm^2 for a round string with the same gauge).
For a round string to have the same area, its gauge would have to be 1.202mm.
Hexagonal shaped strings:
Once again there are two possibilities to measure the gauge, using the altitude or the diagonal.
Let's start with the diagonal:

As you can see, the diagonal equals the diameter of the circumscribing circle (1.25mm). The area of the hexagon = 1.015mm^2 (circle 1.227mm^2). For a circle to have the same area as the hexagon, its diameter would have to be 1.137mm.
Next is the altitude:

In this case, the diameter of the circumscribing circle would be 1.443mm. The area of a hexagon with a 1.25mm gauge in this sense is 1.353mm^2 (1.227mm^2 circle). For a circle to have the same area, it would have to have a diameter of 1.313mm.
Heptagonal shaped strings:
Again, here there's only one way to measure the gauge, namely the altitude:

The diameter of the circumscribing circle here is 1.315mm.
The area of the heptagon is 1.183mm^2 (1.227mm^2 circle).
For a circle to have the same area, its diameter would have to be 1.227mm.
Octagonal shaped strings:
Gauge measured as diagonal:
Diameter of circumscribed circle = diagonal = 1.25mm.
Area of octagon = 1.105mm^2 (1.227mm^2 circle).
Diameter of a circle with the same area = 1.210mm.
Gauge measured as height (A):

Diameter of circumscribing circle = 1.353mm.
Area of octagon = 1.294mm^2 (1.227mm^2 circle).
Diameter of circle with the same area = 1.284mm.
Conclusion:
Now let us sum up what we found, however, using only values with altitudes as measures for the gauge size (simply because this seems like the more realistic assumption). In case you know there is an exception, you can refer to the other values above for guidance


First is a graph, with the amounts of sides of the polygon as the x-axis and the diameter of the circumscribing circle as the y-axis. At first it seems like there is no relationship. However! If you isolate odd and even sided polygons respectively, you will find that the two data sets correlate in a similar way (what seems to be two negative regressive exponential functions, only vertically/horizontally translated). Essentially, the less sides a shape has, the further the maximum distance from the center point to the edges is. However, shapes with even numbers of sides have a relatively higher maximum displacement relative to shapes with odd numbers of sides.
Conclusions:
1) Among odd/even sided strings, those with less sides will feel thicker.
2) For sides with close numbers of sides, even sided shapes will feel thicker.

The next diagram has the amounts of sides of the polygon as the x-axis and the gauge of a round string for which the cross sectional area is equal to that of a 1.25mm shaped string as the y-axis. Here too we can split odd and even sides and find interesting results. Odd sided strings show a positive regressive relationship, whereas even shaped strings show a negative regressive relationship and are always above the level of odd shaped strings! Additionally, it seems like both curves are approaching the regular gauge of the round string (1.25mm), so it seems like that may be a asymptote the two curves approach as they get more and more sides.
Conclusions:
1) Strings with odd numbers of sides have a thinner equivalent gauge than those with even side numbers.
2) The more sides a odd sided string has, the thicker its equivalent gauge is.
3) The more sides a even sided string has, the thinner its equivalent gauge is.
4) Shaped strings with odd numbers of sides have a lower equivalent gauge than comparable round strings.
5) Shaped strings with even numbers of sides have a higher equivalent gauge than comparable round strings.
Thoughts:
The most interesting statistical outlier here is the square shaped string, for its shape takes up the most space (measured as a circumscribing circle, which is the grommet hole shape), and it has by far the highest cross sectional area relative to its gauge. Due to this it is reasonable to suggest that these strings will feel considerably thicker than other shapes (at the same gauge) and that they will be heavier due to their added cross sectional area. Very stiff offerings of these strings are likely to play relatively more uncomfortable and should be treated carefully.
Furthermore, this data seems to suggest that strings with odd numbers of sides play relatively thin, whereas strings with even numbers of sides play relatively thick.
It is entirely possible that these values influence our perception of liveliness and ball feel, which we often attribute to thinner gauges of round strings.
Questions for you: What (other) kinds of implications could these numbers have, and are there any other values that should be calculated?
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