Just like everyone else here, I have a regular opponent who foot faults. Just before he makes contact, his left foot lands about 2.5 feet inside the baseline. It drives me nuts. After playing tonight I started to wonder. Just how much of an advantage is he getting? So I dusted off my high school trig and tried to calculate two things: 1) A 1ft footfault is like being how many inches taller? 1) A 1 ft footfault is like the net being how many inches lower? It's been 15 years since high school, so I'm hoping you guys can check my math. Here's what I came up with: 1ft = 1.71in taller 2ft = 3.43in taller 2.5ft = 4.28in taller 1ft = net .6in lower 2ft = net 1.24in lower 2.5ft = net 1.56in lower For the first calculation, I figured the angle from the top of the net to the service line. Using that angle, I figured the height of the contact point at the baseline that would allow you to hit the ball straight across the top of the net to the service line (not taking into account the width of the ball). Then I shortened the distance to the net, and using the same angle, calculated the height needed to hit straight across the top of the net to the service line. For the second calculation, I kept the contact point height constant and calculated the angle to the service line, which increases as you foot fault. Then I used those angles to calculate the extra inches of net clearance you get as the ball travels across the net to the service line. Hopefully those of you who are smarter than I am can check my math. If my calculations are correct, footfaulting seem to be a real advantage. I would love to be 4 inches taller without sacrificing mobility, and my flat serve would be smoking if the net was an inch and a half lower... CHEATERS!!!!!!!!!!!!!!!!!!!!!!