US open hard courts v AO hard courts:the bounce, which is higher?

Badabing888

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To my eye US Laykold hard courts produce a higher bounce and are slower than the Greenset hard courts of Melbourne.

But According Ai, US open hard courts, which are medium slow produce a lower bounce than the medium fast courts of Melbourne.

Do you agree? Do you think it was a factor in helping Alcaraz in NYC, and why he’s yet to get past the QFs down under?
 
AO surface is just not very lively. It doesn't accentuate spin and the bounce is on the low side, so if you are a good counterpuncher or like to flatten out the ball it's easier to negate a topspin-oriented player. Flat hitter Seb Korda always looks pretty good in Aus (before inevitably failing) while Alcaraz usually looks worse than he really is.
 
AO surface is just not very lively. It doesn't accentuate spin and the bounce is on the low side, so if you are a good counterpuncher or like to flatten out the ball it's easier to negate a topspin-oriented player. Flat hitter Seb Korda always looks pretty good in Aus (before inevitably failing) while Alcaraz usually looks worse than he really is.
Yeh to my eye it looks like AO’s Greenset hard courts don’t accentuate the spin as much as the USO’s Laykold , hence why Sinner and Zverev’s knee bends during rallies as the balls they hit comes in at waist or below hitting zones.

It helps explain why Carlos has yet to reach the semis yet there and why Jannick may have the advantage there if they do meet in next year’s final. All about who gets in that first strike in rallies.

At FO, USO where the surface takes the top spin better Carlos has the advantage, and Wimbledon and AO advantage to Jannick.
 
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