You are funny, "heavier" is not a scientific term, I do not need to look a book or the web, I understand what you are saying but you are leaving out too many variables. Look I have some experience on this, things are way more complicated, for instance the ball has different heights before and after the bounce (potential energy), what happens with this energy after the bounce? I think that part of it is transformed in kinetic energy maybe?
Another thing, why the angle of the bounce is different before and after the bounce? I think we would have to study more the interaction between the ball and the ground having in mind the RPMs of the ball to really have an idea about this.
Since you're being sarcastic, I don't need to be as respectful as I feel I should be, but anyways:
I didn't use heavier as a scientific term. Where did you read that? I wrote the ball would
feel heavier for the player.
The angle will be different before and after the bounce simply because the ball is rotating!!! Of course, the surface of the floor will basically tell you if the variance will be great or not, but the rotation of the ball causes the difference.
You don't need to apply that many variables on the equation since you can assume everything the same: the ball, the court, the players, the racquets, the strings, the weather, the altitude of the location. Simply eliminate all this of the equation. Since you have experience on this, how can you have that left behind?
Last thing: potential energy transforms into kinetic energy when the object changes heights, such as a rollercoaster. A ball bounces on the floor, and since potential energy only applies vertically, you can assume that all potential energy the ball had before bouncing is kept after it bounces - obviously, subtracting the % loss during the impact on the ground.
I completely agree with Fugazi. I'll go a little further with Fugazi's example: Imagine 2 balls free fall, ball F (for flat) without any spin and ball S (for spin) with spin (let's say with Nadal class of spin). Ball F will bounce back upward while ball S will bounce forward. It means ball S had the energy kept (within its spin) to "kick" forward, while F did not. The energy was provided before ball S touched the floor, without any more external force.
Another point of view. When a ball is hit flat it will only have forward force work on it (just ignore the other complicated forces). With topspin, the force worked on the ball is divided to forward force and upper force. Thus if the same amount of force are used on both strokes, the flat one will definitely have faster velocity.
What Fugazi keep repeating is if both strokes produce the same velocity that means there is more force worked on the topspin one compare to the flat one. That additional force kept as the spin will be converted as forward force when it touch the floor. Minus the friction with the floor (and other), the S ball will have a larger forward "kicking" force compared to the F ball. Even without proper calculation it makes a lot of sense that in that case ball S is faster after bouncing.
You completely misunderstand the concept of force in physics. The ball bounces forward because of the rotation applied on it, not because of energy within.
The only other thing you can assume on the equation is the air resistance, which will work much harder on the spinny ball, thus making it describe a different trajectory.
PV, sorry for writing so many off-topic posts. I'll be off this thread and leave it return to its original subject.