Here’s some info from Tennis Warehouse tests:
“It is clear from Figure 10a and 10b that
power potential (ACOR x 100) increases as swingweight and hittingweight are increased due to adding or appropriately redistributing mass.”
We’re talking about racquets with the same swing weight, so that leaves hittingweight as the differentiator in power potential between the two racquets.
“Hittingweight is the "effective" weight (or
effective mass, Me) of the racquet at the impact location.”
All from the same page:
1/Me = (1 / M) + (b2 / I) + (R2 / Iy) (Equation 5)
where, Me is the hittingweight, M is the mass of the racquet, b is the distance from the impact point to an axis through the balance point perpendicular to the racquet, I is the swingweight about the center of mass, R is the distance side-to-side of longitudinal axis of the impact point, and Iy is the twistweight (swingweight about the long axis).
We’re talking about two racquets with the same total mass, so the first part of the equation drops out (1/M). The second part of the equation says that Me gets bigger is I gets bigger; I is the
swing weight about the center of mass, (not the same swing weight we normally talk about which is a few inches from the handle), And yes higher twist weight would help but it’s possible to have the same twist weight in both racquets, so this part of the equation also drops out.
Thus, for two racquets with similar swing weight (Swing weight at ~4 inches or whatever we normally use), similar total weight, and similar balance point, the racquet with more mass further from the balance point, ie, more polarized, has higher hitting weight.
So, re: the two racquets in question: per TWU Customizer, the difference between the two racquets could be 18g located at 13.8in, which is only 1” from the center of mass. That means lighter racquet has more mass farther away from the center of mass.